Ich erhalte
eqn(x) = y(x) == 0 | y(x)*diff(y(x), x, x) + diff(y(x), x)^2 == 0
Wie kann ich auf zweite Bedingung zugreifen?

3 Kommentare

Dyuman Joshi
Dyuman Joshi am 8 Nov. 2023
How do you get this particular expression?
Artur Walter
Artur Walter am 10 Nov. 2023
I typed
f = y(x)^2 * (diff(y(x), x))^2
eqn = functionalDerivative(f,y) == 0
Dyuman Joshi
Dyuman Joshi am 22 Nov. 2023
@Artur Walter, see my answer below.

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Antworten (2)

Dyuman Joshi
Dyuman Joshi am 16 Nov. 2023

1 Stimme

syms y(x)
f = y(x)^2 * (diff(y(x), x))^2;
eqn = functionalDerivative(f,y) == 0;
%Get the equation mentioned in the question description by using simplify()
eqn = simplify(eqn)
eqn(x) = 
%Children of the expression
z = children(eqn)
z = 1×2 cell array
{[y(x) == 0]} {[y(x)*diff(y(x), x, x) + diff(y(x), x)^2 == 0]}
%Access the second condition
condition2 = z{2}
condition2 = 
Aiswarya
Aiswarya am 16 Nov. 2023

0 Stimmen

Hallo, ich würde die Frage auf Englisch beantworten.
(Hi,
I would be answering the question in English)
I understand that on equating a differential expression to zero, you obtained a conditional expression as a result.
The result obtained from the 'functionalDerviative' is a symbolic function and there is no direct way to just extract the second part of the "or" expression. However you can access the second condition by assuming condition for 'y' as shown in the following image.
You can use the assume function (https://www.mathworks.com/help/symbolic/sym.assume.html) to set non zero condition for y. And then simplify the equation to obtain just the second condition.

Produkte

Version

R2023b

Gefragt:

am 8 Nov. 2023

Kommentiert:

am 22 Nov. 2023

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