Ordering a matrix as x increases and y increases
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Hi. I need to remove repeating nodes inside the 'square' array (I need to get only unique rows without repetition).
I tried with the 'unique' command which should be the correct solution, but I would like to confirm.
load square.mat
square = unique(square, 'rows');
figure
plot(square(:,1),square(:,2),'g.','Markersize',15);
axis equal
set(gca, 'YDir','reverse')
Then I need to sort the matrix so that I have the coordinates in the following order:
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Voss
am 25 Okt. 2023
square = unique(square,'rows'); works to remove repeated rows, yes.
In I uderstand the ordering you want, it is to sort by y-coordinate (increasing) and where y-coordinates are equal sort by x-coordinate (increasing). You can sort square in this manner using square = sortrows(square,[2 1]);
load square
square = unique(square,'rows');
square(1:5,:)
square = sortrows(square,[2 1]); % sort by y, then by x
square(1:5,:)
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