a=magic(5)
a = 5×5
17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9
b=[1 3 2 4 5]
b = 1×5
1 3 2 4 5
i want to get:
in 1 column i want to 1 element
in 2 column i want to 3 element
in 3 column i want to 2 element
in 4 column i want to 4 element
in 5 column i want to 5 element
ans:
17 6 7 21 9

 Akzeptierte Antwort

Walter Roberson
Walter Roberson am 8 Okt. 2023

0 Stimmen

a=magic(5)
a = 5×5
17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9
b=[1 3 2 4 5]
b = 1×5
1 3 2 4 5
v = a(sub2ind(size(a), b, 1:size(a,2)))
v = 1×5
17 6 7 21 9

Weitere Antworten (1)

Torsten
Torsten am 7 Okt. 2023
Bearbeitet: Torsten am 7 Okt. 2023

1 Stimme

a = magic(5)
a = 5×5
17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9
b = [1 3 2 4 5]
b = 1×5
1 3 2 4 5
v = arrayfun(@(i)a(b(i),i),1:size(a,2))
v = 1×5
17 6 7 21 9

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