Make a new variable based on data in the cell array.

I have a cell array called C. Each row in C has a different set of integerS stored as a cell

I wan to write a code such that it looks in each row/cell of C, if any integer in the row is equal to 1, it stores in the new variable x, the cell number.

I have the code:

x = []; 
for i = 1:numel(C)
    if any(C{i}==1)
        x(i) = i;      %store index of that cell     %i know this line is the problem
    end
end

problem is this creates length of x same as length of C with zeros in between. I dont want those zeros, instead just a vector of indices where a cell of C has the value 1.

for example right now, the out put is :

1 2 3 0 0 6

where as I want something like this:

1 2 3 6

Answer 1

[Matt J]

x=[1 2 3 0 0 6]

x = 1×6

1 2 3 0 0 6

x=nonzeros(x)'

x = 1×4

1 2 3 6

[Saim Ehtesham]

Thanks for all your answers

Answer 2

[Matt J]

x=[1 2 3 0 0 6]

x = 1×6

1 2 3 0 0 6

x=x(x~=0)

x = 1×4

1 2 3 6

Answer 3

[Matt J]

x=[1 2 3 0 0 6]

x = 1×6

1 2 3 0 0 6

x=x(logical(x))

x = 1×4

1 2 3 6