Filter löschen
Filter löschen

Huber function matlab plotting with two intervals

3 Ansichten (letzte 30 Tage)
Kentman
Kentman am 31 Mär. 2015
Bearbeitet: Walter Roberson am 15 Nov. 2017
Hello,
I was trying to write this simple matlab function:
rho(eps)=0.5*eps^2 for eps<=k
rho(eps)=k*eps-0.5*k^2 for eps>k
for k=1.345
so my solution was:
k=1.345;
for eps=0:0.001:6
if eps<=k
f1=0.5*(eps^2);
else
f1=k*eps-0.5*(k^2);
end %if loop
end %for loop
plot(eps,f1)
There was almost empty graph and sometimes only linear function although this function is supposed to be nonlinear in the first part and linear in the other part.
and also i'm supposed to plot the derivative of this function after this is complete.

Akzeptierte Antwort

Torsten
Torsten am 31 Mär. 2015
k=1.345;
eps=zeros(6001);
f1=zeros(6001);
for i=1:6001
eps(i)=(i-1)*0.001;
if eps(i)<=k
f1(i)=0.5*(eps(i)^2);
else
f1(i)=k*eps(i)-0.5*(k^2);
end %if loop
end;
plot(eps,f1)
Best wishes
Torsten.

Weitere Antworten (3)

Kentman
Kentman am 31 Mär. 2015
Is there a way to plot the derivation of this function directly by matlab or we need to do it by hand then apply the result?

Torsten
Torsten am 31 Mär. 2015
Or more "MATLAB-like":
k=1.345;
eps=0:0.001:6;
f1=zeros(size(eps));
epsf=eps<=k;
f1(epsf)=0.5*eps(epsf).^2;
epsf=eps>k;
f1(epsf)=k*eps(epsf)-0.5*k^2;
plot(eps,f1);
Best wishes
Torsten.

Kentman
Kentman am 31 Mär. 2015
so the final matlab will be
clear all;close all;clc;
k=1.345; eps=zeros(6001); f1=zeros(6001); f2=zeros(6001); for i=1:6001 eps(i)=(i-1)*0.001; if eps(i)<=k f1(i)=0.5*(eps(i)^2); f2(i)=eps(i); else f1(i)=k*eps(i)-0.5*(k^2); f2(i)=k; end %if loop end; %for loop
plot(eps,f1,'k-') hold on plot(eps,f2,'b-')

Kategorien

Mehr zu Optimization finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by