laplace transform of dirac function

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john ne
john ne am 31 Mär. 2015
Kommentiert: Torsten am 31 Mär. 2015
why is it that when im trying to find the laplace transform of a dirac function using the command
laplace(dirac(t+2)),
im getting an answer 0 shouldnt i be getting exp(2*s)? or there is problem since that "c" variable has negative value?

Antworten (1)

Torsten
Torsten am 31 Mär. 2015
syms t s
laplace(dirac(t + 2), t, s)
Best wishes
Torsten.
  1 Kommentar
Torsten
Torsten am 31 Mär. 2015
It will give zero because the mass is concentrated at t=-2 whereas the integral is taken between 0 and infinity.
Best wishes
Torsten.

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