Solving Integral in matlab

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SHAMA NOREEN
SHAMA NOREEN am 17 Apr. 2023
Bearbeitet: Torsten am 17 Apr. 2023
I need to solve this integral in matlab
Where a=1, b=0.71, c=0.53.
I have tried this in matlab
syms s
a=1;
b=0.71;
c=0.53;
f = 1/((s+a^2)*sqrt(((s+a)^2)*((s+b)^2)*((s+c)^2)));
F = int(f, 0, inf)
but I am unable to solve the problem

Antworten (2)

Dyuman Joshi
Dyuman Joshi am 17 Apr. 2023
Bearbeitet: Dyuman Joshi am 17 Apr. 2023
There are cases when int is unable to compute the value of definite integral. In such cases, use vpa to obtain the approximate numerical value
syms s
a = 1;
b = 0.71;
c = 0.53;
f = 1/((s+a^2)*sqrt(((s+a)^2)*((s+b)^2)*((s+c)^2)));
F = int(f, 0, inf);
val1 = vpa(F)
val1 = 
0.67917589608295134074024322188586
You can use vpaintegral directly as well -
val2 = vpaintegral(f,0,inf)
val2 = 
0.679176

Torsten
Torsten am 17 Apr. 2023
Bearbeitet: Torsten am 17 Apr. 2023
syms s
a=sym('1');
b=sym('71/100');
c=sym('53/100');
f = 1/((s+a^2)*(s+a)*(s+b)*(s+c));
F = a*b*c/2*int(f)
F = 
limit(F-subs(F,s,0),s,Inf)
ans = 

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