Hi,
I have a code snippet which updates one of the inputs (struct_data2) using a conditional for loop. I tried to implement a vectorised solution but couldn't achieve it. Support on how to cope with this will be greatly appreciated.
Thanks in advance,
Mel
struct_data1 = struct_data1_root;
struct_data2 = struct_data2_root;
empty_struct_data2_idx = cellfun(@isempty, {struct_data2(:).cid}.');
match_idx = find(empty_struct_data2_idx);
for i = 1: height(struct_data1)
cond = struct_data1(i).nid;
if cond > 1
count = size(match_idx, 1);
rand_idx_id = randperm(count, cond-1);
[struct_data2(match_idx(rand_idx_id)).cid] = deal(struct_data1(i).cid);
match_idx = removerows(match_idx, 'ind', rand_idx_id);
end
end

1 Kommentar

Catalytic
Catalytic am 10 Mär. 2023
Please don't .zip your attachments. It makes it harder for us to extract your data and use the Answers run feature.

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Matt J
Matt J am 10 Mär. 2023
Bearbeitet: Matt J am 10 Mär. 2023

1 Stimme

Perhaps as follows,
empty_struct_data2_idx = cellfun('isempty', {struct_data2(:).cid}.');
match_idx = find(empty_struct_data2_idx);
struct_data1([struct_data1.nid]<=1)=[];
CIDpool=repelem([struct_data1.cid], [struct_data1.nid]-1);
Nmatch=min(numel(match_idx), numel(CIDpool));
CIDpool=num2cell(CIDpool(1:Nmatch));
locations=randperm(numel(match_idx),Nmatch);
[struct_data2(match_idx(locations)).cid]=deal(CIDpool{:});

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R2022b

Gefragt:

am 10 Mär. 2023

Kommentiert:

am 10 Mär. 2023

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