Syntax problem with a user-defined function with sine
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hello, I need to make this function r(𝜃) = 𝜋(3―sin^5*𝜃) as a user-defined function, but I keep getting the "Error using sin - Not enough input arguments." This is how I defined the function so far:
r(theta)=my_function(pi(3-sin.^5*theta));
How do I fix it?
0 Kommentare
Antworten (1)
KSSV
am 3 Mär. 2023
Bearbeitet: KSSV
am 3 Mär. 2023
function r = my_function(thet)
r = pi*(3-sin(theta)^5) ;
end
Save the above, it will be saved on he name my_function.m. Or copy it under your main function code.
You can also define anonymous function as shown below:
r = @(theta) pi*(3-sin(theta)^5) ;
r(pi/2)
Note: your theta shoould be in radians. If you want theta in degrees either convert it to radians or use sind
0 Kommentare
Siehe auch
Kategorien
Mehr zu Logical finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!