I was able to get an answer in my calculator as x = 0.017623 by I want to show this on MATLAB.

 Akzeptierte Antwort

Torsten
Torsten am 14 Feb. 2023
Bearbeitet: Torsten am 14 Feb. 2023

0 Stimmen

f = @(y) cosh(y).*sinh(y)-5/3*y ;
y = 0:0.01:1 ;
plot(y,f(y))
syms x y
assume (x,'real')
eqn = cosh(y).*sinh(y)-5/3*y==0;
ynum = vpasolve(eqn,0.9)
ynum = 
0.9192963573251805500925015133287
format long
xnum = double(solve(ynum-3.79e-5*x^(-2.5)==0,x))
xnum =
0.017622741398035

3 Kommentare

Mason Condren
Mason Condren am 14 Feb. 2023
Is there anyway to do this without plotting and creating a vector. I want it to be as simplistic as possible to show the equation needed to be solved.
Torsten
Torsten am 14 Feb. 2023
Yes, you can remove the first 3 lines of the code if you know that the approximate position of the root of cosh(y).*sinh(y)-5/3*y = 0 is 0.9 without making a plot.
Mason Condren
Mason Condren am 14 Feb. 2023
Okay thank you very much

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Symbolic Math Toolbox finden Sie in Hilfe-Center und File Exchange

Produkte

Version

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by