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Insert new values in specific position after processing

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Elysi Cochin
Elysi Cochin am 12 Feb. 2023
Kommentiert: Elysi Cochin am 12 Feb. 2023
I have a vector A of logical datatype size 5 x 1
A = [1 0 0 1 1 ];
Then I extracted the features where A = 1
ind1 = A(:,1) == 1;
A1 = Feat(ind1,:);
After processing I obtained a new vector
Anew = [ 1 0 1]
Now I want to insert the Anew back to A in the same position to obtain the result as
[1 0 0 0 1]
When I insert the vector back the values are not coming correctly.
Please can someone help me to insert Anew to A in the same position.
The size of vector A can vary

Akzeptierte Antwort

Askic V
Askic V am 12 Feb. 2023
Bearbeitet: Askic V am 12 Feb. 2023
In such stuations, I would keep track of indices of elements in the original vector, use find function.
A = logical([1 0 0 1 1]);
ind = find(A == 1)
ind = 1×3
1 4 5
% processing
Anew = logical([1 0 1]);
A(ind) = Anew
A = 1×5 logical array
1 0 0 0 1
If you really need to change and process the original vector, then instead of removing element in it, place Nan in its position as a placeholder.
  3 Kommentare
Askic V
Askic V am 12 Feb. 2023
Bearbeitet: Askic V am 12 Feb. 2023
In the following example, the result is expected:
A = [5 5 3 2 1 3 4 5 6 2 1 4 5]
A = 1×13
5 5 3 2 1 3 4 5 6 2 1 4 5
ind = find(A == 5) % keep track of the indices
ind = 1×4
1 2 8 13
% processing
%..........
A(ind) = [999.9, 99.9, 9.9, 0.99]
A = 1×13
999.9000 99.9000 3.0000 2.0000 1.0000 3.0000 4.0000 9.9000 6.0000 2.0000 1.0000 4.0000 0.9900
So the logic is good. Please post your code and an example where elements are placed in the wrng positions.
Elysi Cochin
Elysi Cochin am 12 Feb. 2023
Now its working. Thank you

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Weitere Antworten (1)

Voss
Voss am 12 Feb. 2023
A(ind1) = Anew;

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