How can I put variable equal to zero in loop
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in this code
w= input('k=');
for k=1:w
m=sym('U1',[1 k])
end
I need to put U1k in every iteration =0
U11=0
U12=0
U13=0 .......
1 Kommentar
Adham Ahmed
am 8 Feb. 2023
Antworten (3)
Dinesh
am 8 Feb. 2023
Hi Adham Ahmed,
For any input 'w', to create that many number of variables during run time, 'sprintf' function can be used.
Then the 'eval' function can be used to initialize them to zero as you wanted to do.
The following code takes an input 'w' and then creates that many number of variables namely U11, U12, ...., U1w at run time and initializes all of them to zero.
w = input('k='); % takes an input 'w'
for k = 1:w
var_name = sprintf('U%d%d', 1, k); % creates the dynamic variable name
eval([var_name '= 0;']); % initialization to zero
end
In the above code, for an example, if the input 'w' is 3, then you can print 'U13' using
disp(U13);
to confirm the variable creation and value assignment.
2 Kommentare
Steven Lord
am 8 Feb. 2023
Can you dynamically create variables with numbered names like U11, U12, U13, etc.? Yes.
Should you do this? The general consensus is no. That Answers post explains why this is generally discouraged and offers several alternative approaches.
Adham Ahmed
am 8 Feb. 2023
% using loop
w= 10; %input('k=');
for k=1:w
m=sym('U1',[1 k]) == 0;
end
m
you can also do so without using loop
% without loop
m=sym('U1',[1 w]) == 0
Shubham
am 8 Feb. 2023
Here's a code that sets the symbol 'U1k' to zero in each iteration:
w = input('k=');
for k = 1:w
eval(sprintf('U1%d=0', k))
end
1 Kommentar
Adham Ahmed
am 8 Feb. 2023
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