How can repeat the for loop ?

I deployed an object, this object moves from point to point after testing all direction via inner loop, that object chooses the direction that produce maximum value.

My question in the second iteration how can I let the New position (new_max_1 ) be as original position and in the third iteration again the new position be original position and son on.

EXAMPLE, if the original position of the deployed object is [50 -50 ] after testing three angles we found the angle =45 produced maxvalue so that object will select the position with angle=45 which is represents the new_max_1 position, Now in the second Iteration I want the object start from the new position or consider the new_max_1 as original in this equation newPos_1(i,:) =oldPos_1 + dispacement(i,:), in the second or third iteration and so on I want replace the oldPos_1 in new_max_1. Please have a look at the attached code

thanks in advance for any help

oldPos_1 = [50 -50]; % orignal position of an object
v1 =2m/s % velocity of object
for j = 1:100
    
    % loop of point 1
    for bestPos_1 = 1:1
        angles = [23 45 90] % angles in degree
        for i_1=1:1:numel(angles) % 1:1:3
            theta_1 = angles(i) % select angle ascendingly
            displacement(i,:) = [cos(theta_1) .* v1 ,sin(theta_1) .* v1]; % Rotated displacement
            newPos_1(i,:) =oldPos_1 + dispacement(i,:)
            Value_1(i_1) = some calculation depends on the location of that deployed object 
        end
        [maxuValue_1(countmax), idx_max1] = max(Value_1(:));
        angle_produceMaxVlue = angles(idx_max1);
        displacement(bestPos_1) = [cos(angle_produceMaxVlue) .* v1 ,sin(angle_produceMaxVlue) .* v1];
        new_max_1(bestPos_1) = old+ displacement(bestPos_1)
    end
    
end

Answer 1

[Dinesh]

Hi Omar,

From my understanding of the question, assuming new_max1 as newly calculated point, you want to use this as initial point in the next iteration.

To do this update old_pos1 to new_max1 at the end of for loop as shown

    displacement(bestPos_1) = [cos(angle_produceMaxVlue) .* v1 ,sin(angle_produceMaxVlue) .* v1]
    new_max_1(bestPos_1) = old+ displacement(bestPos_1)  
    old_pos1 = new_max1; 
    %updates oldpos1 to new_max1 this will be used as new initial point.
end

Hope this Helps!