Picking an FFT length
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
How could I find the most efficient FFT size greater than N? I know that with fftw "sizes that are products of small factors are transformed most efficiently". I also know that if N=1025, there is going to be a more efficient size than the next power of 2 which is 2048. But in general, what's the best way to find the right size for a given N?
1 Kommentar
Akzeptierte Antwort
Greg Heath
am 21 Okt. 2011
Why not just overlay the times vs size plot for
X = fft(randn(N,M))
when M = 1e4 N1 = 2.^(1:10) % blue and N2 = floor(pi.^(1:6)) %red
or, pick your own sizes.
Hope this helps.
Greg
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Fourier Analysis and Filtering finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!