Hi! How to fix plane position as a 0 degree angle for Phi azimuth angle or how Matlab understand where Phi angle should be drawn?

2 Ansichten (letzte 30 Tage)
I have two angles Theta =60 (polar angle which is <=pi) and Phi = 0 ( which is between 0 and 2pi)
I converted spherical coordinates to cartesian and need to draw vector using one point (1.5; 1.5; 3.0) and two angles.
I also use phi =0 to check if my vector correct. Because if phi=0 then my vector will be strict such as on surface of my box. I dont know how to fix one poisition plane as the start point for Phi angle ( where 0 degree of angles will start). My fixed plane position for the begin of Phi angle will be (0,0,3 0,3,3 0,0,0 0,3,0)
something like this but I dont have ro

Akzeptierte Antwort

Catalytic
Catalytic am 29 Nov. 2022
A = 3.67 * sin(Phi0) * cos(Theta0);
B = 3.67 * sin(Phi0) * sin(Theta0);
C = 3.67 * cos(Phi0);
  1 Kommentar
Aknur
Aknur am 29 Nov. 2022
Bearbeitet: Aknur am 29 Nov. 2022
@Catalytic Thank you
I tried it but it still shows me this one.
If I will accept theta = 0 or phi =0 it is still the same.
I mean that if phi = 0 then the line will lie on the top of the box if theta = 0 then the line will be vertically down.
My angles are: Theta - polar (from 0 to pi) and Phi (azimuth from 0 to 2 pi)
Previous scheme with angles and ro with reverse angels for my case
Could you please suggest another option or what to search? Because I could not understand how Matlab takes a 0 angle. I have edited my question and change the picture. And you can see where will be 0 degrees, 90, 180, 270 degree

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Antennas, Microphones, and Sonar Transducers finden Sie in Help Center und File Exchange

Produkte


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by