怎样画出以下函数的图形? 。

我用的是32位R2009a，32位win7系统

这是程序代码

x= 0:0.1:100;

y1 = (sin(x)+sinh(x))/(cos(x)+cosh(x))

y2 = (1+cos(x).*cosh(x))/((cos(x)+cosh(x)).^2)

y3 = (sin(x)-sinh(x))/(cos(x)+cosh(x))

y4 = sin(x).*sinh(x)/((cos(x)+cosh(x)).^2)

y = 6/(x^2).*((1-3/(2*x).*y1+y2).^2+(3/(2*x).*y3+y4).^2).^(1/2)

plot(x,y)

运行后的结果是>> x = 0:0.1:100;

y1 = (sin(x)+sinh(x))/(cos(x)+cosh(x));

y2 = (1+cos(x).*cosh(x))/((cos(x)+cosh(x)).^2);

y3 = (sin(x)-sinh(x))/(cos(x)+cosh(x));

y4 = sin(x).*sinh(x)/((cos(x)+cosh(x)).^2);

y = 6/(x^2).*((1-3/(2*x).*y1+y2).^2+(3/(2*x).*y3+y4).^2).^(1/2);

plot(x,y)

??? Error using ==> mpower

Matrix must be square.

Answer 1

[pelifih]

x = 0:0.1:100;
y1 = (sin(x)+sinh(x))./(cos(x)+cosh(x));
y2 = (1+cos(x).*cosh(x))./((cos(x)+cosh(x)).^2);
y3 = (sin(x)-sinh(x))./(cos(x)+cosh(x));
y4 = sin(x).*sinh(x)./((cos(x)+cosh(x)).^2);
y = 6./(x.^2).*((1-3./(2*x).*y1+y2).^2+(3./(2*x).*y3+y4).^2).^(1/2);
 plot(x,y)