Using solution from vpasolve and syms for another function
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
A =[ 0 0 0 1.0000 0 0
0 0 0 0 1.0000 0
0 0 0 0 0 1.0000
0 6.5000 -10.0000 -17.5000 0 0
-21.1185 18.1040 5.1540 -3.6920 -2.8128 0.3159
5.0000 -3.6000 0 0 0 -10.9545]
B = [ 0 0
0 0
0 0
26.5000 11.2000
5.5907 -1.6525
40.0000 57.3000]
C = [ 1 0 0 0 0 0
0 1 0 0 0 0
0 0 1 0 0 0]
syms T1 T2 T3 T4 T5 T6
T = [T1 T2 T3 T4 T5 T6];
d = -5;
G = [10 1 5];
vpasolve([T*A - d*T == G*C])
After solving for the values of T1 to T6, i want to use those values to solve for another equation, but when I input T1,T2... into the other equation, it returns the answer in terms of T1 - T6 instead of actual values
e = T*B
how do i get it to return the actual numbers instead of in terms of T1 etc.?
0 Kommentare
Akzeptierte Antwort
KSSV
am 2 Nov. 2022
A =[ 0 0 0 1.0000 0 0
0 0 0 0 1.0000 0
0 0 0 0 0 1.0000
0 6.5000 -10.0000 -17.5000 0 0
-21.1185 18.1040 5.1540 -3.6920 -2.8128 0.3159
5.0000 -3.6000 0 0 0 -10.9545] ;
B = [ 0 0
0 0
0 0
26.5000 11.2000
5.5907 -1.6525
40.0000 57.3000] ;
C = [1 0 0 0 0 0
0 1 0 0 0 0
0 0 1 0 0 0] ;
syms T1 T2 T3 T4 T5 T6
T = [T1 T2 T3 T4 T5 T6];
d = -5;
G = [10 1 5];
s = vpasolve([T*A - d*T == G*C]) ;
T = [double(s.T1) double(s.T2) double(s.T3) double(s.T4) double(s.T5) double(s.T6)];
e = T*B
2 Kommentare
Torsten
am 2 Nov. 2022
You don't need symbolic computations.
A =[ 0 0 0 1.0000 0 0
0 0 0 0 1.0000 0
0 0 0 0 0 1.0000
0 6.5000 -10.0000 -17.5000 0 0
-21.1185 18.1040 5.1540 -3.6920 -2.8128 0.3159
5.0000 -3.6000 0 0 0 -10.9545] ;
B = [ 0 0
0 0
0 0
26.5000 11.2000
5.5907 -1.6525
40.0000 57.3000] ;
C = [1 0 0 0 0 0
0 1 0 0 0 0
0 0 1 0 0 0] ;
d = -5;
G = [10 1 5];
T = ((A.'-d*eye(6))\(G*C).').';
e = T*B
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Equation Solving finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!