I am beginner in matlab, and i struggly to resolve some exercice. can I have some advice according to this task?
1-1/3+1/5-1/7+1/9-..-1/1003

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David Hill
David Hill am 29 Okt. 2022

1 Stimme

n=1:502;
s=sum((-1).^(n+1)./(2*n-1))
s = 0.7849

7 Kommentare

Alonso Mukendi Kalonji
Alonso Mukendi Kalonji am 29 Okt. 2022
how did you get 502 for the loop
VBBV
VBBV am 29 Okt. 2022
The highest term in the fraction of series is 1003. So it can obtained by this way 2*502-1
David Hill
David Hill am 29 Okt. 2022
2*502 -1 = 1003 (last element). 2*n-1 is an expression for odd numbers.
Alonso Mukendi Kalonji
Alonso Mukendi Kalonji am 29 Okt. 2022
This cod are not working
>> a = 1;
k = 502;
for x = 1:k
s = sum(((-1).^(x+1))./(2*(x-1)));
end
disp(s)
-9.9800e-04
No need for a loop. Just run the below code.
x=1:502;
s=sum((-1).^(x+1)./(2*x-1))
s = 0.7849
Maybe of interest:
syms n
s = simplify(symsum((-1)^n/(2*n+1),0,Inf))
s = 
Alonso Mukendi Kalonji
Alonso Mukendi Kalonji am 30 Okt. 2022
I get it!
Thank you very much!

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