I wrote this code using Matlab R2014a in order to loop through a virtual grid:
clear, clc
format long g
load rN_Tang.txt
load aN_Tang.txt
c=aN_Tang(:,:);
f=rN_Tang(:,:);
DepthsA=-c(:,3);
LongitudeA=c(:,1);
DepthsR=-f(:,3);
LongitudeR=f(:,1);
for I=724:747;
J=2:8;
k=1:length(aN_Tang);
l=1:length(rN_Tang);
if ((I<LongitudeA(k)<=I+1 & J<DepthsA(k)<=J+1) & ...
(I<LongitudeR(l)<=I+1 & J<DepthsR(l)<=J+1))
if (isempty(DepthsA(k))==0 & isempty(DepthsR(l))==1)
Zmoy(I,J)=min(DepthsA(k));
elseif (isempty(DepthsA(k))==1 & isempty(DepthsR(l))==0)
Zmoy(I,J)=min(DepthsR(l));
elseif (isempty(DepthsA(k))==1 & isempty(DepthsR(l))==1)
%Ne rien faire, i.e "Void"
elseif (isempty(DepthsA(k))==0 & isempty(DepthsR(l))==0)
zAmin(I,J)=min(DepthsA(k));
DZ(I,J)=min(abs(zAmin(I,J)-DepthsR(l)));
if zAmin(I,J)<=DepthsR(l)
zRmin(I,J)=zAmin(I,J)+DZ(I,J);
else
zRmin(I,J)=zAmin(I,J)-DZ(I,J);
end
Zmoy(I,J)=(zAmin(I,J)+zRmin(I,J))/2;
end
end
Zm=-1*mean(Zmoy(I,J))
end
Matlab response :"
Error using < Matrix dimensions must agree.
Error in plN_Tang (line 60)
if ((I<LongitudeA(k)<=I+1 & J<DepthsA(k)<=J+1) & (I<LongitudeR(l)<=I+1 & J<DepthsR(l)<=J+1))"
What's wrong with the loop?
PS:I'd be so grateful if someone has an idea about this issue!

 Akzeptierte Antwort

dpb
dpb am 16 Mär. 2015
Bearbeitet: dpb am 22 Mär. 2015

0 Stimmen

...
for I=724:747;
J=2:8;
k=1:length(aN_Tang);
l=1:length(rN_Tang);
if ((I<LongitudeA(k)<=I+1 & J<DepthsA(k)<=J+1) & ...
(I<LongitudeR(l)<=I+1 & J<DepthsR(l)<=J+1))
...
J, k, and l are invariant and so should be outside the loop...
J=2:8;
k=1:length(aN_Tang);
l=1:length(rN_Tang);
for I=724:747;
if ((I<LongitudeA(k)<=I+1 & J<DepthsA(k)<=J+1) & ...
(I<LongitudeR(l)<=I+1 & J<DepthsR(l)<=J+1))
...
Now I is a single value and while k is a vector of some unknown length but thus the returned subarray LongitudeA(k) is also of that length (presuming the size of the array is commensurate with that and the values are within the array bounds). But, you have a disparate size between a single value I and a vector LongitudeA(k) which causes a Matlab failure. Similar problems occur with the other arrays.
Not precisely sure what you're really after here so not positive the right coding solution...

2 Kommentare

Marouane  Berrada
Marouane Berrada am 22 Mär. 2015
Hi, What I want is to find the lesser value of the Vector "DepthsA" through a grid of 0.2x0.2.
Anyway, thank you very much for responding
dpb
dpb am 22 Mär. 2015
I don't know what that means, precisely, what's wrong with
min(DepthsA)
??

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Gefragt:

am 16 Mär. 2015

Kommentiert:

dpb
am 22 Mär. 2015

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by