Heat transient equation not executing

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Reji G
Reji G am 17 Sep. 2022
Kommentiert: Torsten am 17 Sep. 2022
I want to implement this formula in matlab. But i couldn't. So it'd be great if anyone can help me. Where x&t ranges from 0.1 to 10.
  2 Kommentare
Torsten
Torsten am 17 Sep. 2022
Please show us your attempt.
Reji G
Reji G am 17 Sep. 2022
Verschoben: Star Strider am 17 Sep. 2022
clc;
close all;
clear all;
T1=300;
Ti = 350;
L = 10;
alpha = 100;
syms n
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,9)
T(x,t) = T1+((4/pi)*(Ti-T1)*T);

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Antworten (1)

Torsten
Torsten am 17 Sep. 2022
The terms in your series do not agree with the formula you posted.
You must decide which one is correct and which one is wrong.
clc;
close all;
clear all;
T1 = 300;
Ti = 350;
L = 10;
alpha = 100;
syms n t x
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,20);
T = T1+4/pi*(Ti-T1)*T;
T = matlabFunction(T);
x = 0:0.1:L;
t = 0:0.1:1;
[X,TIME] = meshgrid(x,t);
surf(TIME,X,T(TIME,X))
  2 Kommentare
Reji G
Reji G am 17 Sep. 2022
I need Temperature value(T(x,t)). an x y plot is required. Not the graph you plotted
Torsten
Torsten am 17 Sep. 2022
clc;
close all;
clear all;
T1 = 300;
Ti = 350;
L = 10;
alpha = 100;
syms n t x
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,20);
T = T1+4/pi*(Ti-T1)*T;
T = matlabFunction(T);
x = 0:0.01:L;
t = 0.1;
figure(1)
plot(x,T(t,x))
x = L/2;
t = 0:0.001:0.5;
figure(2)
plot(t,T(t,x))

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