Finding root of nonlinear functions
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University Glasgow
am 8 Sep. 2022
Kommentiert: Sam Chak
am 8 Sep. 2022
Please, how do I find all the roots this function:
y-0.8193318913*tanh(y)+0.2931044702e-2*tanh(y)/(0.7500000000e-3*y^2-0.1622336517e-1) = 0
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Torsten
am 8 Sep. 2022
f = @(y)(y-0.8193318913*tanh(y)).*(0.7500000000e-3*y.^2-0.1622336517e-1)+0.2931044702e-2*tanh(y);
fun = @(y)f(y)./(0.7500000000e-3*y.^2-0.1622336517e-1);
y = -6:0.01:6;
plot(y,f(y))
x0 = [-5 -4];
s(1) = fzero(f,x0);
x0 = [-1 1];
s(2) = fzero(f,x0);
x0 = [4 5];
s(3) = fzero(f,x0);
s
fun(s)
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Sam Chak
am 8 Sep. 2022
Read about fzero().
The solution may look like this:
fun = @(y) y - 0.8193318913*tanh(y) + (0.2931044702e-2)*tanh(y)./(0.7500000000e-3*y.^2 - 0.1622336517e-1);
y0 = 0; % initial guess
y = fzero(fun, y0)
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