M.file implementing the formula below using either Mat-lab or octave
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ephraim matloba
am 20 Feb. 2015
Kommentiert: Stalin Samuel
am 21 Feb. 2015
In the following, R can take any value between 5 and 6. Work out the value of I for R = 5.00, 5.01, 5.02, ..., and 6. Then find the average value of I. I= 30/(R*(sqrt(R^2+15*pi^2))
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Stalin Samuel
am 20 Feb. 2015
r = 5.00:0.01:6.00
for i=1:numel(r)
R=r(i)
I(i)= 30/(R*(sqrt(R^2+15*pi^2)))
end
avg =mean(I)
2 Kommentare
Titus Edelhofer
am 20 Feb. 2015
Hi Samuel,
there is no need to use a loop, if you replace "30/" by "30./" and the "*" and "^2" by ".*" and ".^2" ...
Titus
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