simulation of dde problem
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Good evening sir i am trying to find simulation of dde model problem but i got error. I. request you sir please help me by resolving this error
beta = 1.9;
a1 = 0.3;
a2 = 0.2;
gamma1= 0.01;
gamma2= 0.01;
gamma3= 0.05;
mu= 0.05;
tau =14;
N=1;
d1 = 0.04;
d2 = 0.02;
ddeSEIQR = @(t,y,Z)[N-beta*y(1)*y(3)/N-mu*y(1);...
(beta*y(1)*y(3)/N)-beta*exp(-mu*tau)*Z(1,1)*Z(3,1)/N-a1*y(2)-gamma1*y(2)-mu*y(2);...
beta*exp(-mu*tau)*Z(1,1)*Z(3,1)/N-a2*y(3)-gamma2*y(3)-d1*y(3)-mu*y(3);...
a1*y(2)+a2*y(3)-d2*y(4)-gamma3*y(4)-mu*y(4);...
gamma1*y(2)+gamma2*y(3)+gamma3*y(4)-mu*y(5)];
sol = dde23(ddeSEIQR,[14,1],[0.999,0,0.001,0,0],[0,200] ) ;
figure;
plot(sol.x,sol.y(1,:))
hold on
plot(sol.x,sol.y(2,:),'-')
hold on
plot(sol.x,sol.y(3,:),'--')
hold on
plot(sol.x,sol.y(4,:),'--')
hold on
plot(sol.x,sol.y(5,:),'--')
hold off
title('Equilibrium points for SEAIQR Model');
label ('time(days)');
label('solution y');
legend('S', 'E','I', 'Q','R');
ERROR:
Error using vertcat
Dimensions of arrays being concatenated are not consistent.
Error in
SEIQR_dde>@(t,y,Z)[N-beta*y(1)*y(3)/N,-mu*y(1);(beta*y(1)*y(3)/N)-beta*exp(-mu*tau)*Z(1,1)*Z(3,1)/N-a1*y(2)-gamma1*y(2)-mu*y(2);beta*exp(-mu*tau)*Z(1,1)*Z(3,1)/N-a2*y(3)-gamma2*y(3)-d1*y(3)-mu*y(3);a1*y(2)+a2*y(3)-d2*y(4)-gamma3*y(4)-mu*y(4);gamma1*y(2)+gamma2*y(3)+gamma3*y(4)-mu*y(5)]
(line 15)
ddeSEIQR = @(t,y,Z)[N- beta*y(1)*y(3)/N -mu*y(1);
Error in dde23 (line 228)
f0 = feval(ddefun,t0,y0,Z0,varargin{:});
Error in SEIQR_dde (line 21)
sol = dde23(ddeSEIQR,[14,1],[0.999,0,0.001,0,0],[0,200] ) ;
4 Kommentare
Torsten
am 10 Aug. 2022
what is [14,1] and how did i take ?
Did you read the documentation of dde23 ?
14 and 1 are the lags in your differential equations.
I wonder why you specified two lags because in your equations, you only refer to the first (14) with the terms
Z(1,1) (which means y1(t-14)) and
Z(3,1) (which means y3(t-14)).
Antworten (0)
Siehe auch
Kategorien
Mehr zu Numerical Integration and Differential Equations finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!