Finding an element in table without using if_else condition

% Input

A = ["I";"I";"R"];

B = [1;1;0];

C = [1;0;2];

D = [0;2;2];

E = ["R";"S";"I"];

% Create Table

Table_A = table(A,B, C, D,E);

% The output E depends on the inputs ( A,B,C and D ). For eg.

% Only if ( A = "I" & B = 1 & C = 0 & D = 0 ), E = "R"

Question: I want to get the corresponding element in E without using an if else condition since there are a lot more elements and therefore a lot more conditions for getting each element in E.

Thank you.

Answer 1

[Benjamin Thompson]

You can do some operations on the Table variables to get index vectors:

>> Table_A.A

ans =

3×1 string array

"I"

"I"

"R"

>> Table_A.A == "I"

ans =

3×1 logical array

1

1

0

Then use the index vectors to calculate the values for E, then copy the new values for E into the table.

[Shrinish Donde]

Thanks Benjamin. Simpler than I thought !

/Shrinish