The program cannot work

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Shuoze Xu
Shuoze Xu am 4 Jul. 2022
Kommentiert: Shuoze Xu am 5 Jul. 2022
Hi.
There is a review question without answer.
Here is the question
A function is defined as
function [dice] = roll(sides)
dice(0) = randi(sides);
dice(1) = randi(sides);
end
If the function is called as follows:
[roll1,roll2] = dice(6);
and the random numbers generated are 1 and 6. What will be the value od roll1 and roll2?
My first question is that what is roll1 and roll2? i confused for the function. the return value is only one, why it can be returned two values as roll1 and roll2 ?
Then, the function name is roll, why use dice to call the function?
Thank you all.

Akzeptierte Antwort

Siraj
Siraj am 4 Jul. 2022
Bearbeitet: Siraj am 4 Jul. 2022
Hi,
It is my understanding that you want to know the value of roll1 and roll2,
“[roll1, roll2] = dice (6)”.
This will lead to an “Too many output arguments” error because the function has only one return object that is “dice”.
The name of the function is “roll” therefore we cannot call the function using “dice()”.
The correct way to call the function is “d = roll(6) “ where “d” is a random integer array of dimension 1X2 and values in range 1 to 6.
For further help you can see functions in MATLAB.
d = roll(6)
d = 1×2
3 2
function [dice] = roll(sides)
dice(1) = randi(sides);
dice(2) = randi(sides);
end

Weitere Antworten (1)

Chunru
Chunru am 4 Jul. 2022
Bearbeitet: Chunru am 4 Jul. 2022
% [roll1,roll2] = dice(6)
% The above is wrong in syntax as the function has only ONE return object
% dice (as an array).
% The correct way to call the function
d = roll(6)
d = 2×1
4 3
function [dice] = roll(sides)
% dice(0) = randi(sides);
% dice(1) = randi(sides);
dice = randi([1 6], [2 1]); % generate 2x1 random integer in range [1 6]
end

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