passing a function to another function
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
R yan
am 3 Feb. 2015
Kommentiert: R yan
am 3 Feb. 2015
Hi
I am trying to pass the following function "haar" to the function integral. I am getting the following error. plz suggest. thanks
function val = haar(x)
if ((0<=x) && (x<0.5))
val=1;
elseif ((0.5<= x) && (x < 1))
val =-1;
else
val =0;
end
end
EDU>> fhnadle=@haar;
EDU>> integral(fhnadle,0,1)
Operands to the || and && operators must be convertible to logical scalar values
0 Kommentare
Akzeptierte Antwort
Sean de Wolski
am 3 Feb. 2015
Bearbeitet: Sean de Wolski
am 3 Feb. 2015
integral calls the function with a vector x, you're expecting x to be a scalar in your haar function. E.g:
>> [1 2 3] && 1
The easiest thing for you to do is to modify haar to use logical indexing on val:
function val = haar(x)
val = zeros(size(x)); % assume zero
val(0<=x & x<0.5) = 1; % set ones
val(0.5<=x & x<1) = -1; % set -1s
end
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Discrete Multiresolution Analysis finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!