Fast function application

2 Ansichten (letzte 30 Tage)
Mateusz
Mateusz am 29 Sep. 2011
Hi,
Let a be n-dimensional vector, B n-by-n dimensional matrix, f(a, b) - binary function that operates on two vectors, and returns scalar as a result. Is there fast way (no-loops) to implement application of this function to vector a and every column of matrix B? More precisely forall_j r(j) = f(a, B(:, j))?
  1 Kommentar
Mateusz
Mateusz am 29 Sep. 2011
I think I cannot repmat vector 'a' since f has to work explicitly on vectors.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 29 Sep. 2011
These days, "no loops" is not necessary any faster.
You can use
arrayfun(@(K) f(a,B(:,K)), 1:size(B,2))
but that will probably not be any faster than a loop.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by