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Why the responses of the following equations are nothing?

1 Ansicht (letzte 30 Tage)
Marzieh Nodeh
Marzieh Nodeh am 21 Apr. 2022
Kommentiert: Star Strider am 25 Apr. 2022
I'm trying to find aeq from the following equations. There are 3 equations with 3 unknowns. but the final response is empty brackets for all unknowns. Could you help me to solve this equation.
Regards,
syms ae gama A
eq1= (23.4255*(ae^3))+(1.2308e-06*ae)+gama
eq2= (A/(6*23.4255))-((2*1.2308e-06)/A)-ae
eq3= A-((((-108*gama)+(12*(sqrt(3*(((4*(1.2308e-06^2))+(27*(gama^2)*23.4255))/23.4255)))))*(23.4255^2)))^(1/3)
eqs= [eq1, eq2, eq3]
[ae,gama,A]=vpasolve(eqs, [ae,gama,A])
%reported results
ae =
[ empty sym ]
gama =
[]
A =
[]

Antworten (1)

Star Strider
Star Strider am 21 Apr. 2022
Use solve then vpa
syms ae gama A
eq1= (23.4255*(ae^3))+(1.2308e-06*ae)+gama
eq1 = 
eq2= (A/(6*23.4255))-((2*1.2308e-06)/A)-ae
eq2 = 
eq3= A-((((-108*gama)+(12*(sqrt(3*(((4*(1.2308e-06^2))+(27*(gama^2)*23.4255))/23.4255)))))*(23.4255^2)))^(1/3)
eq3 = 
eqs= [eq1, eq2, eq3]
eqs = 
[ae,gama,A]=solve(eqs, [ae,gama,A]);
Warning: Possibly spurious solutions.
ae = vpa(ae,7)
ae = 
gama = vpa(gama,7)
gama = 
A = vpa(A,7)
A = 
Also consider double instead of vpa, depending on the result you want.
.
  6 Kommentare
Marzieh Nodeh
Marzieh Nodeh am 25 Apr. 2022
Perfect. Thank you very much for your help.
Star Strider
Star Strider am 25 Apr. 2022
My pleasure!
If my Answer helped you solve your problem, please Accept it!
.

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