Write a random row vector x of size 1x10000. Find in the same for loop the number of elements of x that are btw 0.2 and 0.4.

Can you help me? I solved this problem but I am not sure it's true because when I run the code, answer is too small, like 0 or 1.

Write a random row vector x of size 1x10000. Find in the same for loop the number of elements of x that are btw 0.2 and 0.4.

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% add in the same for loop the number of the elements of x that are btw 0.2 and 0.4

% assign x with 10000 random numbers

x = rand(10000,1);

% assign theCount with 0

theCount = 0;

% assign countBetween with 0

countBetween = 0;

% loop runs for 1 to 10000

% check the number is less than 0.2

% increment count by 1

for i = 1:10000

if(x(i) < 0.2)

theCount = theCount + 1;

end

end

% check the number is btw 0.2 and 0.4

% increment count by 1

if (x(i) > 0.2 && x(i) < 0.4)

countBetween = countBetween + 1;

end

Answer 1

[Voss]

The check for x(i) between 0.2 and 0.4 also has to be inside the for loop (or in its own separate for loop); otherwise you are only ever checking the last element of x, since i is 10000 after the loop finishes.

% add in the same for loop the number of the elements of x that are btw 0.2 and 0.4
% assign x with 10000 random numbers
x = rand(10000,1);
% assign theCount with 0
theCount = 0;
% assign countBetween with 0
countBetween = 0;
% loop runs for 1 to 10000
% check the number is less than 0.2
% increment count by 1
for i = 1:10000
    if(x(i) < 0.2)
        theCount = theCount + 1;
    end
% end
% check the number is btw 0.2 and 0.4
% increment count by 1
    if (x(i) > 0.2 && x(i) < 0.4)
        countBetween = countBetween + 1;
    end
end
disp(theCount);

        2024

disp(countBetween);

        2047

[kerem yaman]

Thank you so much.

[Voss]

You're welcome!