how do i fix inline function error?

i m trying to make matrix (4x16)

in forloop, three modifies of 'a' are series (1 to infinite)

it works untill i added 4th a series (which means inline function. i think this line makes error)

i should add inline function and show series's sum to 160 on 4th row in matrix A

and I got this error

>> work5(0.5)

error: sum: wrong type argument 'class'

function A=work5(x)

m=1;

for k=10:10:160
  n=1:k;
  a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
  A(1,m)=a;
  
  a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
  A(2,m)=a;
  
  a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
  A(3,m)=a;
  
  a= sum(inline('log(n)./(n.^2)','n'));
  A(4,m)=a;
  
  m=m+1;
  
end

Answer 1

[Riccardo Scorretti]

Hi,

you can try this:

work5(0.5)

ans = 4×16

0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.2361 0.0183 0.0047 0.0021 0.0012 0.0008 0.0005 0.0004 0.0003 0.0002 0.0002 0.0002 0.0001 0.0001 0.0001 0.0001 0.0001 2.6037 2.8014 2.8760 2.9152 2.9394 2.9558 2.9677 2.9766 2.9837 2.9893 2.9939 2.9978 3.0011 3.0040 3.0064 3.0086 0.6185 0.7415 0.7927 0.8215 0.8401 0.8532 0.8630 0.8706 0.8767 0.8817 0.8859 0.8895 0.8926 0.8952 0.8976 0.8997

function A=work5(x)
m=1;
fun = @(n) log(n)./(n.^2);                    % ***
for k=10:10:160
  n=1:k;
  a= sum(nthroot(n.^2,5)./((3.^n).*(n+1)));
  A(1,m)=a;
  
  a= sum((3*n.^2+n)/(2*n.^4+nthroot(n,2)));
  A(2,m)=a;
  
  a= sum((nthroot(37,2)*n.^3)/((2*n.^3)+(3*n.^2)));
  A(3,m)=a;
  
  % a= sum(inline('log(n)./(n.^2)','n'));     % ***
  a = sum(fun(n));
  A(4,m)=a;
  
  m=m+1;
end
end

The problem seems to be related with the deprecated function inline.

[Ann Lee]

thank you it worked!!! have a nice day!!!