Filter löschen
Filter löschen

Removing repeated in order elements from array?

4 Ansichten (letzte 30 Tage)
Nicholas Kavouris
Nicholas Kavouris am 30 Mär. 2022
Kommentiert: Voss am 30 Mär. 2022
I have an array like [ 1 1 1 2 2 3 3 3 1 1 1 2 2 4 4 4 5 5 6]
Is there a method which will produce array [ 1 2 3 1 2 4 5 6] and remove all repeating orderly values but not remove all duplicates?
have tried code below with no luck
for k=length(array):-1:1
if array(k)==array(k+1)
array(k)=[]
end
end

Antworten (2)

Rik
Rik am 30 Mär. 2022
No need for a loop (even if you should have replaced length by numel):
data=[ 1 1 1 2 2 3 3 3 1 1 1 2 2 4 4 4 5 5 6];
L=diff(data)==0; % note: this is 1 element shorter that data itself
data(L)=[]
data = 1×8
1 2 3 1 2 4 5 6

Voss
Voss am 30 Mär. 2022
Your approach will work; you just have to start at the second-to-last element instead of the last:
array = [ 1 1 1 2 2 3 3 3 1 1 1 2 2 4 4 4 5 5 6];
for k=length(array)-1:-1:1
if array(k)==array(k+1)
array(k)=[];
end
end
array
array = 1×8
1 2 3 1 2 4 5 6
Here's another approach:
array = [ 1 1 1 2 2 3 3 3 1 1 1 2 2 4 4 4 5 5 6];
array(diff(array) == 0) = [];
array
array = 1×8
1 2 3 1 2 4 5 6
  3 Kommentare
Torsten
Torsten am 30 Mär. 2022
Bearbeitet: Torsten am 30 Mär. 2022
Why not ? I get
array = [2]
It's because diff(array) has one element less than array.
Voss
Voss am 30 Mär. 2022
As @Torsten says, it should still work (both ways work):
array = [2 2 2 2 2 2 2];
for k=length(array)-1:-1:1
if array(k)==array(k+1)
array(k)=[];
end
end
array
array = 2
array = [2 2 2 2 2 2 2];
array(diff(array) == 0) = [];
array
array = 2

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Data Type Conversion finden Sie in Help Center und File Exchange

Produkte


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by