rename files using data in cell array

hi, I have a list of 135 .mat files with complete file path. I have to take subjectid from the file path ( for eg. /project/brain/12345/matrix_456.mat) I want to copy these files into a new folder and rename them with brain_id_filename. So for this case it will be brain_12345_matrix_456.mat. I was able to copy these files into a new folder using copyfile but i am unable to rename them. thanks in advance.

Antworten (1)

Voss
Voss am 18 Mär. 2022
Bearbeitet: Voss am 18 Mär. 2022

0 Stimmen

You can rename files using copyfile() or movefile().
In either case the destination argument would be the new name of the file (not a folder), and it's best to use full absolute paths, e.g.:
copyfile('/home/project/brain/12345/matrix_456.mat','/home/project/brain_12345_matrix_456.mat');

2 Kommentare

pallavi sri
pallavi sri am 18 Mär. 2022
Thanks but i have 135 . mat files, so i was running this in loop, with destination as the destination directory
Voss
Voss am 18 Mär. 2022
Bearbeitet: Voss am 18 Mär. 2022
If you want to rename the files, destination will have to be the new file name. It will be different each time through the loop.
You can set up a cell array containing the new file names, e.g.:
old_files = { ...
'/project/brain/12345/matrix_456.mat'; ...
'/project/brain/12345/matrix_789.mat'; ...
'/project/brain/99999/matrix_000.mat'}; % you say you have this already
new_files = strrep(old_files,filesep(),'_') % something like this, maybe not exactly
new_files = 3×1 cell array
{'_project_brain_12345_matrix_456.mat'} {'_project_brain_12345_matrix_789.mat'} {'_project_brain_99999_matrix_000.mat'}
for ii = 1:numel(new_files)
copyfile(old_files{ii},new_files{ii});
end

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Data Import and Analysis finden Sie in Hilfe-Center und File Exchange

Produkte

Version

R2015a

Gefragt:

am 18 Mär. 2022

Bearbeitet:

am 18 Mär. 2022

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by