# How to reduce matrix size conditionally?

4 views (last 30 days)
Andi on 17 Mar 2022
Edited: Davide Masiello on 17 Mar 2022
Hi everyone,
My dataset consists of 194 rows and 5 column. in each row either a non-zero value or NaN. I require to pick the non-zero value (only one). There may be more than one non-zero values but all are same, so i need only one. As a resul the size of output matrix will be 194 by 1.
Thansk.

Voss on 17 Mar 2022
Edited: Voss on 17 Mar 2022
Here's one way:
N = max(N_total,[],2);
Andi on 17 Mar 2022
Thanks

Simon Chan on 17 Mar 2022
Try this:
mean(N_total,2,'omitnan')

Davide Masiello on 17 Mar 2022
Edited: Davide Masiello on 17 Mar 2022
You could use the max function. See below
% here I reproduce your type of matrix
A = rand(194,1);
A = [A,A,A,A,A];
A(logical(randi([0,1],size(A)))) = nan
A = 194×5
NaN NaN NaN 0.2306 0.2306 NaN NaN NaN 0.2761 NaN NaN NaN NaN NaN 0.3897 NaN NaN 0.5264 0.5264 0.5264 0.4432 NaN NaN 0.4432 0.4432 0.6612 NaN 0.6612 0.6612 NaN NaN NaN 0.3336 NaN 0.3336 0.3968 NaN 0.3968 0.3968 0.3968 NaN 0.7869 0.7869 0.7869 NaN 0.4621 NaN NaN NaN 0.4621
% Here I perform the required task
A = max(A,[],2)
A = 194×1
0.2306 0.2761 0.3897 0.5264 0.4432 0.6612 0.3336 0.3968 0.7869 0.4621

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