How to reduce matrix size conditionally?

1 Ansicht (letzte 30 Tage)
Andi
Andi am 17 Mär. 2022
Bearbeitet: Davide Masiello am 17 Mär. 2022
Hi everyone,
My dataset consists of 194 rows and 5 column. in each row either a non-zero value or NaN. I require to pick the non-zero value (only one). There may be more than one non-zero values but all are same, so i need only one. As a resul the size of output matrix will be 194 by 1.
Thansk.

Akzeptierte Antwort

Voss
Voss am 17 Mär. 2022
Bearbeitet: Voss am 17 Mär. 2022
Here's one way:
N = max(N_total,[],2);

Weitere Antworten (2)

Simon Chan
Simon Chan am 17 Mär. 2022
Try this:
mean(N_total,2,'omitnan')

Davide Masiello
Davide Masiello am 17 Mär. 2022
Bearbeitet: Davide Masiello am 17 Mär. 2022
You could use the max function. See below
% here I reproduce your type of matrix
A = rand(194,1);
A = [A,A,A,A,A];
A(logical(randi([0,1],size(A)))) = nan
A = 194×5
NaN NaN NaN 0.2306 0.2306 NaN NaN NaN 0.2761 NaN NaN NaN NaN NaN 0.3897 NaN NaN 0.5264 0.5264 0.5264 0.4432 NaN NaN 0.4432 0.4432 0.6612 NaN 0.6612 0.6612 NaN NaN NaN 0.3336 NaN 0.3336 0.3968 NaN 0.3968 0.3968 0.3968 NaN 0.7869 0.7869 0.7869 NaN 0.4621 NaN NaN NaN 0.4621
% Here I perform the required task
A = max(A,[],2)
A = 194×1
0.2306 0.2761 0.3897 0.5264 0.4432 0.6612 0.3336 0.3968 0.7869 0.4621

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Tags

Produkte

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by