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Fourier series doesn't approximate with bigger number of points

1 Ansicht (letzte 30 Tage)
reddlno
reddlno am 14 Mär. 2022
Kommentiert: Torsten am 15 Mär. 2022
Hello.
I am trying to approximate a function using fourier series, but using a larger input of points N I get an aproximation bigger than the original graph. I can't seem to find where the problem is any help is appreciated. First plot is the function, then it's the fourier series versus precise graph and then An and Bn koeficient correlation from N.
code:
clc
clear
%conditions
T=3;
h=0.1;
a=-3;
b=3;
N=36;
x=a:h:b;
n1=0;
%original function
for iks=a:h:b
n1=n1+1;
graf1(1,n1)=iks;
graf1(2,n1)=funk(iks);
end
%plot
plot(graf1(1,:),graf1(2,:));
ylabel('y')
xlabel('x')
%Fourier series and aproximation
A0=0;
for iks2=0:h:T
A0=A0+funk(iks2);
end
A0=A0.*2.*h./T;
AnBn=zeros(3,N);
for nr=1:N
for n2=-T:h:T
AnBn(1,nr)=AnBn(1,nr)+funk(n2)*cos(2*nr*pi*n2/T);
AnBn(2,nr)=AnBn(2,nr)+funk(n2)*sin(2*nr*pi*n2/T);
end
end
AnBn=AnBn.*h./T;
n3=0;
aprox1=zeros(2,(b-a)./h);
for iks3=a:h:b
aprox=0;
for k=1:N
aprox=aprox+(AnBn(1,k).*cos(2*k*pi*iks3/T)+AnBn(2,k).*sin(2*k*pi*iks3/T));
end
aprox=aprox+A0/2;
n3=n3+1;
aprox1(1,n3)=iks3;
aprox1(2,n3)=aprox;
end
%ploting
figure
plot(aprox1(1,:),aprox1(2,:),'b',graf1(1,:),graf1(2,:),'r');
ylabel('y')
xlabel('x')
legend('Aproksimated f','Original f')
for nr1=1:N
AnBn(3,nr1)=nr1;
end
figure
scatter(AnBn(3,:),AnBn(1,:),'r')
ylabel('An')
xlabel('N')
figure
scatter(AnBn(3,:),AnBn(2,:))
ylabel('Bn')
xlabel('N')
funk:
function [y] = funk(x)
T=3;
x1=1.0;
x2=x1+0.5*pi;
if (x<0)
while (x<0)
x=x+T;
end
elseif (x>T)
while (x>T)
x=x-T;
end
end
if (0<=x && x<x1)
y=0;
elseif (x1<=x && x<=x2)
y=sin(2*(x-x1)).^2;
elseif (x2<x && x<=T)
y=0;
end
end

Antworten (1)

Benjamin Thompson
Benjamin Thompson am 14 Mär. 2022
The fourier series coefficients should be divided by pi when calculating the reconstruction:
  2 Kommentare
reddlno
reddlno am 15 Mär. 2022
And that should fix it? Just dividing coefficients a0, an, ab by pi?
Torsten
Torsten am 15 Mär. 2022
According to your graph, there is a factor 3 between the two curves ...

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