Select August data from a vector column in the format YYYYMMDD

3 Ansichten (letzte 30 Tage)
Hi,
I have two vector columns, one containing the dates in the format YYYYMMDD for 10 years, and in the other column the amount of rainfall in mm. I want to create a matrix, or two vector columns, containing only the months of august with the corresponding rainfall. Any ideas how to achieve this?
Thanks in advance

Akzeptierte Antwort

Roger Wohlwend
Roger Wohlwend am 11 Dez. 2014
First convert your time vector into a vector that contains the date as a number.
Date = datenum(Date_Vector,'YYYYMMDD');
Now search for August.
q = month(Date) == 8;
Create your matrix.
AugustRainfallMatrix = [Date(q), Rainfall(q)];

Weitere Antworten (1)

Peter Perkins
Peter Perkins am 11 Dez. 2014
Bearbeitet: Peter Perkins am 11 Dez. 2014
Are the dates strings, or numbers?
If you have access to R2014b, you could do either of these, depending on which you have:
>> c % cell array of strings
c =
'20141201'
'20141202'
'20141203'
'20141204'
'20141205'
>> month(datetime(c,'Format','yyyyMMdd'))
ans =
12
12
12
12
12
>> x % integer values
x =
20141201
20141202
20141203
20141204
20141205
>> month(datetime(x,'convertFrom','YYYYMMDD'))
ans =
12
12
12
12
12

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