Exponential Function Plotting From Reverse

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tinkyminky93
tinkyminky93 am 26 Feb. 2022
Kommentiert: Star Strider am 26 Feb. 2022
Hello,
I want to plot the graph of exponential function but in reverse order. For example I want this plot to start from 5 and decrease until 0 not from 0 to 5. I will also use drawnow to animate the plot. How can I do that time operation? My code is like that. I want this operation comes reversely.
clear all
close all
t = 0:1:150;
x = log(1004*t);
figure
for i=1:numel(t)
plot(t(i),x(i),'.','Color','r')
hold on
drawnow
ylim([0 30])
xlim([0 150])
grid minor
end

Akzeptierte Antwort

Star Strider
Star Strider am 26 Feb. 2022
I initially could not get the 'XDir' to 'reverse' before the loop. Apparently it is necessary to plot something and then set the axes to 'reverse'.
Try this —
t = 150:-1:0;
x = log(1004*t);
figure
Ax = axes;
plot(Ax,NaN,NaN)
Ax.XDir = 'reverse';
hold on
for i=1:numel(t)
plot(Ax,t(i),x(i),'.','Color','r')
drawnow
ylim([0 30])
xlim([0 150])
grid minor
end
The animation will not show here, so run it offlline to see the effect.
.
  2 Kommentare
tinkyminky93
tinkyminky93 am 26 Feb. 2022
Bearbeitet: tinkyminky93 am 26 Feb. 2022
The only thing that we should do is setting t= 150:-0.1:0
I solved the problem. When I run your code, it is the same as KSSV's graph.
I don't need to reverse the axes. I just need to reverse the time. :)
Star Strider
Star Strider am 26 Feb. 2022
I don't need to reverse the axes. I just need to reverse the time. :)’
That was not obvious from the way the question was stated. (I initially reversed ‘t’, however it took a bit of experimentation to also reverse the x-direction. I wanted to provide a complete solution.)

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KSSV
KSSV am 26 Feb. 2022
Bearbeitet: KSSV am 26 Feb. 2022
clear all
close all
t = 0:1:150;
x = log(1004*t);
figure
plot(t,x,'Color','r')
grid minor
set(gca,'XDir','reverse')
  4 Kommentare
KSSV
KSSV am 26 Feb. 2022
t = 0:1:150;
x = log(1004*t);
figure
plot(t,x,'Color','r')
grid minor
tinkyminky93
tinkyminky93 am 26 Feb. 2022
Okey sir, that is not what I want to explain but thanks for your effort.

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