Why are the "For loops" not looping?
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Christopher Scott
am 21 Feb. 2022
Kommentiert: per isakson
am 22 Feb. 2022
prompt = 'Enter Integer Value For N ';
N = input(prompt);
prompt = 'Enter Integer Value For E ';
E = input(prompt);
prompt = 'Enter Value For deltaE ';
deltaE = input(prompt);
[allState{N:-1:1}] = ndgrid(1:E); % Create N col matrix with all possible energy configurations
allState = reshape(cat(N+1,allState{:}),[],N);
allStateSum = sum(allState,2); % Sum a row of allState and place values into a col matrix
allStateSum = transpose(allStateSum);
deltaEmatrix = (0:deltaE:E+20); % create col matrix that increments by deltaE from 0 up to E
Omega = zeros(1,length(deltaEmatrix)); % Initialize Omega matrix, ready to accept values
p = 0; % The first "for loop" ascends from 1 to # of rows of deltaEmatrix
for pIndex = 1:length(deltaEmatrix)
p = p +1;
q = 0;
disp(pIndex)
for qIndex = 1:length(allStateSum) % Second "for loop" ascends from 1 to # of rows of allStateSum
q = q +1;
if allStateSum(1,q) >= deltaEmatrix(1,q) && allStateSum(1,q) < deltaEmatrix(1,q+1)
Omega(1,p) = Omega(1,p)+1;
else
return % This section loops through allStateSum and checks if value is between
end % the deltaE intervals. If true, add 1 to the pth row of Omega.
% Each value in allStateSum
% is checked
end
end
1 Kommentar
Akzeptierte Antwort
Voss
am 22 Feb. 2022
I bet it's because of that return statement. When the code encounters a return the function is exited immediately (thus no more loop iterations will occur).
0 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!