Cube Every Third Integer Using Nested Loop Structure

Attempting to cube every third integer in an array using a for and if loop structure. Note, this is my first time creating a nested loop structure and need simple straightforward explanation as to why the code does not work.
for i = [1:16]
if (i/3==0)
i^3
else
i
end
end

Antworten (1)

for i = [1:16]
if (mod(i,3)==0)
i^3
else
i
end
end
i = 1
i = 2
ans = 27
i = 4
i = 5
ans = 216
i = 7
i = 8
ans = 729
i = 10
i = 11
ans = 1728
i = 13
i = 14
ans = 3375
i = 16

2 Kommentare

Thank you!
VBBV
VBBV am 30 Mär. 2022
if this solved your problem, please accept the answer :) thanks

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Gefragt:

am 8 Feb. 2022

Kommentiert:

am 30 Mär. 2022

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