Suitable input for a function handle

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Hellow friends,
I need to do something which I explain through a simple example. Consider the following
F=@(x,y,z)[x.*z.^2.*y;3.*x-y-2.*z;x.^2+y.^2+z.^2];
A1=[1 2 3];B1=num2cell(A1);
A2=[4 5 6];B2=num2cell(A2);
F(B1{:})
F(B2{:})
ans =
18
-5
14
ans =
720
-5
77
Now, I desire to do all the above calculations at once. I mean, I wish to do something as bellow (which throughs error)
>> A=[1 2 3;4 5 6];
B=num2cell(A);
F(B)
Not enough input arguments.
Error in @(x,y,z)[x.*z.^2.*y;3.*x-y-2.*z;x.^2+y.^2+z.^2]
I wish to get the following answer:
18 720
-5 -5
14 77
Any idea?
Thanks in advance,
Babak

Accepted Answer

Walter Roberson
Walter Roberson on 4 Feb 2022
F = @(x,y,z)[x.*z.^2.*y;3.*x-y-2.*z;x.^2+y.^2+z.^2];
A = [1 2 3;4 5 6];
B = cellfun(@transpose, num2cell(A, 1), 'uniform', 0)
B = 1×3 cell array
{[1 4]} {[2 5]} {[3 6]}
F(B{:})
ans = 3×2
18 720 -5 -5 14 77
  3 Comments
Walter Roberson
Walter Roberson on 4 Feb 2022
num2cell() is basically an easier interface around mat2cell.
output = num2cell(A, 1)
is
tsize = size(A);
nd = length(tsize);
temp = cell(1,nd);
temp{1} = ones(1,tsize(1));
for K = 2 : nd; temp{K} = tsize(K); end
output = mat2cell(A, temp{:})
(The code can be made shorter under the assumption that A has exactly 2 dimensions.)

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