Error assigning variable in loop

1 Ansicht (letzte 30 Tage)
mashtine
mashtine am 13 Nov. 2014
Kommentiert: mashtine am 13 Nov. 2014
It is beyond me why I cannot figure this out. The debugger points to the line 'wsstd(i,1) = fricvelo.*4;' but I think it has to do with my if statement as even when the condition is failed, a calculation is still done. L(1,1) for instance is -0.393. I am sure my tired eyes just can't find the simple problem.
wsstd = zeros(length(ws),1);
for i = 1:11950;
if L(i,1) >= -500 && L(i,1) <= -50
wsstd(i,1) = fricvelo.*4;
else
wsstd(i,1) = 0;
end
end
  2 Kommentare
Rick Rosson
Rick Rosson am 13 Nov. 2014
Bearbeitet: Rick Rosson am 13 Nov. 2014
  1. Please post the exact and complete error message.
  2. What is the result of typing size(fricvelo) at the command prompt?
mashtine
mashtine am 13 Nov. 2014
Hi Rick,
Here is the message:
Subscripted assignment dimension mismatch.
Error in ERA_Suomi_parametrization (line 43)
wsstd(i,1) =
43 wsstd(i,1) = fricvelo.*4
size(fricvelo) is (39928,1) where the #rows is the same as the length(ws)

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Orion
Orion am 13 Nov. 2014
You're trying to insert a 39928x1 vector in only one element of wsstd.
size(wsstd(i,1)) == 1 for any i.
So you have a dimension problem.
you can only put a scalar in wsstd(i,1).
You need to change something (like fricvelo(i) ?...)
  1 Kommentar
mashtine
mashtine am 13 Nov. 2014
Wow! How did I not see such an obvious answer! Sorry for waste of time Orion. Thanks

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by