How can i Assign the value of cut-off frequency ?

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3lewwi
3lewwi am 2 Jan. 2022
Kommentiert: 3lewwi am 3 Jan. 2022
f=[0.01:0.01:2e04];
s=2*pi*f;
wc1=j*2*pi*10;
wc2=j*2*pi*500;
H1=(s+wc1).^-1;
H2=(s.^2+(wc1+wc2)*s+wc1*wc2).^-1;
MH1=abs(H1);
MH2=abs(H2);
semilogx(f,20*log10(MH1/max(MH1)),'r')
hold on
semilogx(f,20*log10(MH2/max(MH2)),'k')

Antworten (1)

Chunru
Chunru am 2 Jan. 2022
f=[0.01:0.01:2e04];
s=2*pi*f;
wc1=j*2*pi*10; % fc
wc2=j*2*pi*500;
H1=(s+wc1).^-1;
H2=(s.^2+(wc1+wc2)*s+wc1*wc2).^-1;
MH1=abs(H1);
MH2=abs(H2);
semilogx(f,20*log10(MH1/max(MH1)),'r')
hold on
semilogx(f,20*log10(MH2/max(MH2)),'k')
yline(-3); % -3dB
xline(10);
grid on
  3 Kommentare
Chunru
Chunru am 3 Jan. 2022
The slope for H1 is roughly 20dB/decative.
The slope for H2 is varying with frequency. Between 10 and 500Hz, the slope for H2 is roughly 20dB/decative. Beyond 500Hz, the slope is roughly 40dB/decative.
3lewwi
3lewwi am 3 Jan. 2022
big thanks broo

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