plugging in a function inside fittype, error

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Alvaro Sanchez
Alvaro Sanchez am 10 Dez. 2021
Beantwortet: Walter Roberson am 22 Dez. 2021
Hello. I'm new in matlab. I'm currently trying to use the fittype function to later on use to fit.
I have a truncated exponetial whcih i define in the following matlab function.
function [yf] = Exp_t(x3,a,m)
%x and y data are arrays with size 20x1
%a and m are unknown coeficients to be fitted.
for i=1:20
if x3(i)<0 %truncation
yf(i,1)=0;
elseif (x3(i)>=0) && (x3(i)<=a)
yf(i,1)=(1-exp(-m*x3(i)))/(1-exp(-m*a)); %exponential fucntion
elseif x3(i)>a %truncation
yf(i,1)=1;
end
end
end
I then insaert this function in my main script
%truncated exponential fit.
y3=(table1{:,4}); %data from column 4 table1
x3=(table1{:,3}); %data from column 3 table1
%inserting Exp_t(x3,a,m) into fittype function
ft = fittype( 'Exp_t(x3,a,m)','independent', {'x3'}, 'dependent', {'yf'},'coeff',{'a','m'});
%fit(x3,y3,ft,'Robust','on')
I've spent more than two days trying to fix this, any help is much apreciated.
I receive the following errors:
Error using fittype/testCustomModelEvaluation (line 12)
Expression Exp_t(x3,a,m) is not a valid MATLAB expression, has non-scalar coefficients, or cannot be evaluated:
Error in fittype expression ==> Exp_t(x3,a,m)
??? Index exceeds the number of array elements (7).
Error in fittype>iCreateFittype (line 373)
testCustomModelEvaluation( obj );
Error in fittype (line 330)
obj = iCreateFittype( obj, varargin{:} );
Error in Project_2 (line 105)
ft = fittype( 'Exp_t(x3,a,m)','independent', {'x3'}, 'dependent', {'yf'},'coeff',{'a','m'});
Caused by:
Error using fittype/evaluate>I_ERROR_FCN_ (line 179)
Error in fittype expression ==> Exp_t(x3,a,m)
??? Index exceeds the number of array elements (7).

Akzeptierte Antwort

Gargi Patil
Gargi Patil am 21 Dez. 2021
Hi,
This error can be resolved by declaring the size of the output array yf beforehand in the function Exp_t as follows:
function [yf] = Exp_t(x3, a, m)
%x and y data are arrays with size 20x1
%a and m are unknown coeficients to be fitted.
yf = zeros(size(x3, 1), 1);
....
end
  2 Kommentare
Alvaro Sanchez
Alvaro Sanchez am 21 Dez. 2021
thanks, that worked but also had to remove the brackets.
Matt J
Matt J am 22 Dez. 2021
@Alvaro Sanchez If it worked, please Accept-click the answer.

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Weitere Antworten (1)

Walter Roberson
Walter Roberson am 22 Dez. 2021
ft = fittype( 'Exp_t(x3,a,m)','independent', {'x3'}, 'dependent', {'yf'},'coeff',{'a','m'});
Instead of using a quoted character expression, use an anonymous function.

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