Storing regression coefficients in a loop

3 Ansichten (letzte 30 Tage)
Elin Jacobs
Elin Jacobs am 7 Dez. 2021
Kommentiert: Elin Jacobs am 8 Dez. 2021
Hello,
I'm doing a simple linear regression on a 20x30x365 matrix (latitude, longitude, time). I want to store the slope and p - value for each lat/lon pair such that the end result are two 20x30 matrices. I'm attaching some dummy data and my attempted code below. Thank you.
X = size(prec,3);
i = 20;
j = 30;
slopes = zeros(i,j);
pvals = zeros(i,j);
for i = 1:i
for j= 1:j
mdl = fitlm(X,prec(i,j,:));
slope = table2array(mdl.Coefficients(2,1));
pval = table2array(mdl.Coefficients(2,4));
slopes = slope(i,j);
pvals = pval(i,j);
end
end

Akzeptierte Antwort

VBBV
VBBV am 7 Dez. 2021
Bearbeitet: VBBV am 8 Dez. 2021
slopes(i,j) = slope;
pvals(i,j) = pval;
  2 Kommentare
VBBV
VBBV am 8 Dez. 2021
n = size(prec,3);
X = (1:1:n)';
I = 20; % change this variable with a differnt letter
J = 30; % same here
slopes = zeros(I,J);
pvals = zeros(I,J);
for i = 1:I
for j= 1:J
y = reshape(prec(i,j,:),[n,1]);
mdl = fitlm(X,y);
slope = table2array(mdl.Coefficients(2,1));
pval = table2array(mdl.Coefficients(2,4));
slopes(i,j) = slope;
pvals(i,j) = pval;
end
end
When the for loop runs, its using concurrent values of i and j. Change the symbols as above and run it
Elin Jacobs
Elin Jacobs am 8 Dez. 2021
My bad, this works great! thank you!!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (0)

Produkte


Version

R2016a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by