Creating a set range for a function
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Sebastian Sunny
am 3 Dez. 2021
Kommentiert: Alan Stevens
am 3 Dez. 2021
Hi guys,
Im trying to create a if fucnction where my equation works for a set range of x values.
My code at the moment:
x = (mydata);
if (x < 3) && (x > 25)
windTurbineRotorModel(x == 0);
elseif (3 < x) && (x < 11)
windTurbineRotorModel = (0.042)*(1/2)*(1.23)*pi()*((171/2)^3)*(x).^2;
elseif (11 < x) && (x < 25)
windTurbineRotorModel = (0.042)*(1/2)*(1.23)*pi()*((171/2)^3)*(x).^2;
end
Thanks
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Akzeptierte Antwort
Alan Stevens
am 3 Dez. 2021
(x < 3) && (x > 25)
An individual element of x can't be both less than 3 and greater than 25 at the same time.
If here are many values of x (as is likely), then do the tests element by element. e.g. something like:
for i = 1:numel(x)
if (x(i) < 3) || (x(i) > 25)
windTurbineRotorModel(x == 0);
elseif (3 < x(i)) && (x(i) < 11)
windTurbineRotorModel = (0.042)*(1/2)*(1.23)*pi()*((171/2)^3)*(x(i)).^2;
elseif (11 < x(i)) && (x(i) < 25)
windTurbineRotorModel = (0.042)*(1/2)*(1.23)*pi()*((171/2)^3)*(x(i)).^2;
end
end
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