tic toc inside a timeit
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Hi,
I have a function "test". Inside this test function, I have a for loop that goes from 1 to N. Since I want to know the average time for each iteration, I put tic /toc, and a variable called "Time_for" will give me the average time, as you can see in the code below
test(x)
tic
for i=1:N
some operations
% code
end
Time_for=toc/N % this result is displayed in the command window, and not saved as an output of the function
Now, I want to compute the time execution of the function. For this purpose, in the main of the program, I use the timeit function, as you can see below
f=@()test(x);
time_function=timeit(f);
My problem is that, when I run timeit, the variable "Time_for", that should just be displayed only once, it is actually displayed 10 times. And for each of these 10 times, the value slightly changes.
Why the toc function, inside a timeit, is computed multiple times?
Best,
Maria
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Sean de Wolski
am 27 Okt. 2014
This is actually mentioned in the tips at the bottom of the doc for timeit
Unexpected results occur when you call tic and toc inside of timeit. If you are going to do this, be sure to assign an output to tic
myt = tic;
mystuff
toc(myt)
Of course printing to the command line takes some time too, so I would also disable that if really trying to time the code.
1 Kommentar
Maria
am 27 Okt. 2014
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