how to do this

y=6[2A-0.5sin(A)]/pi for 0<= x <= pi/2

Answer 1

[Mischa Kim]

Agil, what is A? Is it supposed to be x? At any rate, in MATLAB language you'd use something like

 x = 0:0.1:pi/2;              % crates a vector of x vals
 y = 6*(2*x - 0.5*sin(x))/pi  % computes y as a function of x
 plot(x,y)

Answer 2

[Shrirang]

Yes above answer is right but If you are looking for system implementation then u can implement in simulink as in diagram or in m script you can write as follows (same as above answer but some changes) if (x>=0) && (x<=pi/2) y = 6*(2*x - 0.5*sin(x))/pi; else y = 0; % Depends on your requirement end