Find value of x, from max y (graph)
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figure(2);
vel = diff(y)./diff(x);
plot(x(1:end-1), vel)
display(max(findpeaks(vel)))
x(max(findpeaks(vel)));
Trying to find the value of x corresponding to the maximum value of y, for this velocity vs time graph.
displays error due to logical or integer access.
0 Kommentare
Antworten (2)
Mischa Kim
am 17 Okt. 2014
Andrew, check out
x = 0:0.1:6;
y = sin(x + 0.5);
vel = diff(y)./diff(x);
plot(x(1:end-1), vel,x(vel == max(vel)),max(vel),'dr')
0 Kommentare
Michael Haderlein
am 17 Okt. 2014
Bearbeitet: Michael Haderlein
am 17 Okt. 2014
I'd actually prefer the following:
...
vel = diff(y)./diff(x);
[maxvel,ind]=max(vel);
plot(x(1:end-1),vel,x(ind),maxvel,'or')
If you have a large number of velocities, this one here will be faster. For a small number, it just doesn't matter.
5 Kommentare
Michael Haderlein
am 17 Okt. 2014
What do you mean? You can, for instance, use the Data Cursor tool in the menu toolbar. Or you use the handles (plot_handles=get(gca,'children');) of the plots and then extract the x and the y data of the plots (x=get(plot_handles(1),'xdata');).
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