mean of matrix elements

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john creighton
john creighton am 15 Okt. 2014
Kommentiert: john creighton am 16 Okt. 2014
hey all. i have a 5760x1 matrix. i need to find the average of the first 10 elements, remove the 10 elements and replave with the averaged number, find the average of the next 10 elements, remove those 10 elements and replace with average and so on.... could anyone give me an insight as to how to do this? much appreciated john

Akzeptierte Antwort

Sean de Wolski
Sean de Wolski am 15 Okt. 2014
B = mean(reshape(x,10,[]))'
Where x is your original column vector and B is the mean of every 10x1 chunk

Weitere Antworten (3)

Andrew Reibold
Andrew Reibold am 15 Okt. 2014
Bearbeitet: Andrew Reibold am 15 Okt. 2014
myMatrix = rand(5760,1)
for jj = 1:576
moving_avg(jj,1) = mean(myMatrix(jj*10-9:jj*10));
end
Will make a matrix called 'moving_avg' where each point represents the average of each set of 10 points.
Is that what you wanted? It will be 1/10 the size.
  1 Kommentar
Andrew Reibold
Andrew Reibold am 15 Okt. 2014
Its very easy to replace every single point with the average too if thats what you need. (Same size, but every set of 10 numbers are all the same averaged number.)

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Andrei Bobrov
Andrei Bobrov am 16 Okt. 2014
I want have 'vote' too!
out = accumarray(ceil((1:numel(x))'/10),x(:),[],@mean);
  2 Kommentare
Sean de Wolski
Sean de Wolski am 16 Okt. 2014
b=blkproc(rand(5760,1),[10,1],@mean)
I can't think of a solution shorter than my reshape one in terms of Code Golf?
john creighton
john creighton am 16 Okt. 2014
haha. yours works too...so well deserved 'vote' :)

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john creighton
john creighton am 16 Okt. 2014
Both answers worked perfectly. Thanks guys. sorry can only accept one answer lol

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