number of elements of each unique values in a matrix

I can use unique(A) to get an array of each unique value in the matrix A. However, how can I also get an array of the number of elements with each unique value? For instance

B=unique(A) might give:

 [1; 4; 6; 8];

and an additional step might give:

 [10; 1; 5; 7];

if there were 10 entries of 1, 1 entry of 4, 5 entries of 6, etc.

I know I can easily do this by doing find(A==B(1,1))... etc. but if the array of uniques is long then this should be very inefficient.

Is there a function like unique which returns the number of elements for each unique value without much additional computation??

Thanks

Answer 1

[Andrei Bobrov]

B = unique(A);
out = [B,histc(A,B)];

[Christopher]

I don't understand the output of 'out'? It's definitely not a simple list of corresponding amounts of elements with certain unique values.

Edit:

I think this is what I am looking for:

 out=sum(histc(O,B),2)

[Sean de Wolski]

It should be, Christopher.

[Sean de Wolski]

A = [1;1;1;2;3;3];
B = unique(A);
out = [B,histc(A,B)]

out =
   1     3
   2     1
   3     2

First column is value, second is number of occurrences