Matlab Error after executing the code
2 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Dear sir/Madam
I have the following Matlab code.
clear all
clc
kc=[1 2 3 4 5 6 7 8 9 0];
k12=200;
k34=300;
new1=1:1:10;
for h1=1:length(new1);
for l1=1:length(new1);
K(h1,l1)=[k12 -k12 0 0;-k12 kc(h1,l1)+k12 -kc(h1,l1) 0;0 -kc(h1,l1) k34+kc(h1,l1) -k34;0 0 -k34 k34];
end
end
After executing it, an error is displayed as "Unable to perform assignment because the left and right sides have a different number of elements." Kindly provide any suggestions to avoid this error.
2 Kommentare
Sreedevi K
am 4 Nov. 2021
You are trying to save a 4*4 matrix (RHS) into a single element (LHS) which is not allowed.
Antworten (2)
Sreedevi K
am 4 Nov. 2021
You have to save into a cell array or a 3D matrix. As shown below:
kc=[1 2 3 4 5 6 7 8 9 0];
k12=200;
k34=300;
new1=1:1:10;
count = 0 ;
for h1=1:length(new1)
for l1=1:length(new1)
count = count+1 ;
K{count}=[k12 -k12 0 0;-k12 kc(h1,l1)+k12 -kc(h1,l1) 0;0 -kc(h1,l1) k34+kc(h1,l1) -k34;0 0 -k34 k34];
end
end
0 Kommentare
VBBV
am 30 Nov. 2021
clear all
clc
kc=[1 2 3 4 5 6 7 8 9 0];
k12=200;
k34=300;
new1=1:1:10;
for l1=1:length(new1)
K(:,:,:,:,l1)=[k12 -k12 0 0;-k12 kc(l1)+k12 -kc(l1) 0;0 -kc(l1) k34+kc(l1) -k34;0 0 -k34 k34];
end
K
clear K
TT = 1
for l1=1:length(new1)
K{TT}=[k12 -k12 0 0;-k12 kc(l1)+k12 -kc(l1) 0;0 -kc(l1) k34+kc(l1) -k34;0 0 -k34 k34];
TT = TT+1;
end
K
You need one for loop only to compute the matrix, Also, you were getting error because, when you access more elements from matrix than its actual dimension. You can do it using cell array as below
0 Kommentare
Siehe auch
Kategorien
Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!